4x^2-56x+132=0

Solution for 4x^2-56x+132=0 equation:

4x^2-56x+132=0

a = 4; b = -56; c = +132;
Δ = b2-4ac
Δ = -562-4·4·132
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-32}{2*4}=\frac{24}{8}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+32}{2*4}=\frac{88}{8}
=11
$